login
A218302
E.g.f. A(x) satisfies A( x/(exp(x)*cosh(x)) ) = exp(4*x)*cosh(4*x).
11
1, 4, 40, 496, 7488, 134784, 2836736, 68635648, 1881948160, 57777184768, 1965962575872, 73503311167488, 2997314388623360, 132455836580577280, 6308164435588415488, 322185156718017642496, 17571327124936467677184, 1019377026461494381903872
OFFSET
0,2
COMMENTS
More generally, if A( x/(exp(t*x)*cosh(t*x)) ) = exp(m*x)*cosh(m*x),
then A(x) = Sum_{n>=0} m*(n*t+m)^(n-1) * cosh((n*t+m)*x) * x^n/n!.
FORMULA
E.g.f.: A(x) = Sum_{n>=0} 4*(n+4)^(n-1) * cosh((n+4)*x) * x^n/n!.
From Seiichi Manyama, Apr 23 2024: (Start)
E.g.f.: A(x) = 1/2 + 1/2 * exp( 4*x - 4*LambertW(-x * exp(x)) ).
a(n) = 2 * Sum_{k=0..n} (k+4)^(n-1) * binomial(n,k) for n > 0.
G.f.: 1/2 + 2 * Sum_{k>=0} (k+4)^(k-1) * x^k/(1 - (k+4)*x)^(k+1). (End)
EXAMPLE
E.g.f.: A(x) = 1 + 4*x + 40*x^2/2! + 496*x^3/3! + 7488*x^4/4! +...
where
A(x) = cosh(4*x) + 4*5^0*cosh(5*x)*x + 4*6^1*cosh(6*x)*x^2/2! + 4*7^2*cosh(7*x)*x^3/3! + 4*8^3*cosh(8*x)*x^4/4! + 4*9^4*cosh(9*x)*x^5/5! +...
PROG
(PARI) {a(n)=local(Egf=1, X=x+x*O(x^n), R=serreverse(x/(exp(X)*cosh(X)))); Egf=exp(4*R)*cosh(4*R); n!*polcoeff(Egf, n)}
for(n=0, 25, print1(a(n), ", "))
(PARI) /* Formula derived from a LambertW identity: */
{a(n)=local(Egf=1, X=x+x*O(x^n)); Egf=sum(k=0, n, 4*(k+4)^(k-1)*cosh((k+4)*X)*x^k/k!); n!*polcoeff(Egf, n)}
for(n=0, 25, print1(a(n), ", "))
KEYWORD
nonn
AUTHOR
Paul D. Hanna, Oct 25 2012
STATUS
approved