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a(n) = A361072(n)/n!^3.
0

%I #30 Jan 03 2025 09:28:59

%S 0,3,84,4935

%N a(n) = A361072(n)/n!^3.

%C The next term would not be an integer.

%H Andrew Vince and Miklos Bona, <a href="https://arxiv.org/abs/1204.3842">The Number of Ways to Assemble a Graph</a>, arXiv preprint, arXiv:1204.3842 [math.CO], 2012. See Theorem 24.

%H Andrew Vince and Miklos Bona, <a href="https://doi.org/10.37236/2644">The Number of Ways to Assemble a Graph</a>, The Electronic Journal of Combinatorics, Volume 19, Issue 4 (2012), Article P54.

%Y Cf. A361072.

%K nonn,fini,full,less

%O 0,2

%A _N. J. A. Sloane_, Oct 08 2012