OFFSET
1,2
COMMENTS
Number of digits in 6^k is equal to floor(1 + k*log_10(6)).
MATHEMATICA
k = 0; Join[{1}, Table[While[d = IntegerDigits[6^k]; prt = Partition[Differences[d], n - 1, 1]; ! MemberQ[prt, Table[0, {n - 1}]], k++]; Length[d], {n, 2, 8}]] (* T. D. Noe, Oct 03 2012 *)
CROSSREFS
KEYWORD
nonn,base
AUTHOR
V. Raman, Sep 27 2012
EXTENSIONS
a(11) added by V. Raman, Nov 23 2013
STATUS
approved