|
|
A214990
|
|
Second nearest integer to n*r, where r = (1+ sqrt(5))/2, the golden ratio.
|
|
2
|
|
|
1, 4, 4, 7, 9, 9, 12, 12, 14, 17, 17, 20, 22, 22, 25, 25, 27, 30, 30, 33, 33, 35, 38, 38, 41, 43, 43, 46, 46, 48, 51, 51, 54, 56, 56, 59, 59, 62, 64, 64, 67, 67, 69, 72, 72, 75, 77, 77, 80, 80, 82, 85, 85, 88, 88, 90, 93, 93, 96, 98, 98, 101, 101, 103, 106, 106
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,2
|
|
COMMENTS
|
Let {x} denote the fractional part of x. The second nearest integer to x, denoted by s(x), is defined to be ceiling(x) if {x} < 1/2 and floor(x) if {x} >= 1/2. If x is not an integer, there are exactly two integers k such that |k-x|<1; one is round(x) = floor(x+1/2), and the other is s(x).
Let J(n) be the n-th number k for which s((k+1)*r) > s(k*r). The golden ratio appears to be the only number x for which J(n) = floor(nx) for all n>=0. In this case, J = A000201.
Let f(n) = 0 if s(n) = s(n+1) and f(n) = 1 otherwise; then f is the infinite Fibonacci word A005713 = 1-A005614.
In A214990, replace each repeated term by 1 and all others by 0; the result is A005713 (prefixed by 0).
|
|
LINKS
|
|
|
EXAMPLE
|
n . . n*r . . nearest integer . second nearest
1 . . 1.618... . 2 . . . . . . . 1 = a(1)
2 . . 3.236... . 3 . . . . . . . 4 = a(2)
3 . . 4.854... . 5 . . . . . . . 4 = a(3)
4 . . 6.472... . 6 . . . . . . . 7 = a(4)
5 . . 8.090... . 8 . . . . . . . 9 = a(5)
|
|
MATHEMATICA
|
r = GoldenRatio; f[x_] := If[FractionalPart[x] < 1/2, Ceiling[x], Floor[x]]
Table[f[r*n], {n, 1, 100}] (* A214990 *)
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|