

A214962


Least m>0 such that F(nm) divides F(2n+2m), where F = A000045 (Fibonacci numbers).


1



1, 1, 2, 1, 2, 3, 4, 3, 2, 7, 4, 9, 6, 3, 8, 13, 6, 15, 4, 7, 11, 19, 8, 5, 13, 9, 12, 25, 6, 27, 16, 11, 17, 7, 12, 33, 19, 13, 8, 37, 14, 39, 22, 9, 23, 43, 16, 21, 10, 17, 26, 49, 18, 11, 24, 19, 29, 55, 12, 57, 31, 21, 32, 13, 22, 63, 34, 23, 14, 67, 24, 69, 37, 15
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OFFSET

2,3


LINKS

Clark Kimberling, Table of n, a(n) for n = 2..1000


EXAMPLE

Write x#y if xy is false; then 8#987, 5#2584, 36765 so a(7) = 3.


MATHEMATICA

Table[m = 1; While[! Divisible[Fibonacci[2n+2m], Fibonacci[n  m]], m++]; m, {n, 2, 100}]


CROSSREFS

Cf. A214917.
Sequence in context: A196686 A213088 A169809 * A076258 A259576 A030330
Adjacent sequences: A214959 A214960 A214961 * A214963 A214964 A214965


KEYWORD

nonn,easy


AUTHOR

Clark Kimberling, Jul 31 2012


STATUS

approved



