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 A214493 Numbers of the form ((6k+5)^2+9)/2 or 2(3k+4)^2-9. 3
 17, 23, 65, 89, 149, 191, 269, 329, 425, 503, 617, 713, 845, 959, 1109, 1241, 1409, 1559, 1745, 1913, 2117, 2303, 2525, 2729, 2969, 3191, 3449, 3689, 3965, 4223, 4517, 4793, 5105, 5399, 5729, 6041, 6389, 6719, 7085, 7433, 7817, 8183, 8585, 8969, 9389, 9791, 10229, 10649, 11105, 11543, 12017, 12473, 12965, 13439, 13949 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,1 COMMENTS For every n=2k the triple (a(2k-1)^2, a(2k)^2 , a(2k+1)^2) is an arithmetic progression, i.e., 2*a(2k)^2 = a(2k-1)^2 + a(2k+1)^2. In general a triple((x-y)^2,z^2,(x+y)^2) is an arithmetic progression if and only if x^2+y^2=z^2. The first differences of this sequence is the interleaved sequence 6,42,24,60,42,78.... = 9*n*(39-27*(-1)^n)/2. LINKS Index entries for linear recurrences with constant coefficients, signature (2,0,-2,1). FORMULA a(n) = 2*a(n-1)-2*a(n-3)+a(n-4). G.f.: (17-11*x+19*x^2-7*x^3)/((1+x)*(1-x)^3). a(n) = (6*n*(3*n+10)+27*(-1)^n+41)/4. 2*a(2n)^2 = a(2n-1)^2 + a(2n+1)^2. EXAMPLE For n = 7, a(7)=2*a(6)-2*a(4)+a(3)=2*269-2*149+89=329. MATHEMATICA LinearRecurrence[{2, 0, -2, 1}, {17, 23, 65, 89}, 60] (* Harvey P. Dale, Aug 07 2015 *) PROG I:=[17, 23, 65, 89]; [n le 4 select I[n] else 2*Self(n-1)-2*Self(n-3)+Self(n-4): n in [1..75]]; CROSSREFS Cf. A178218, A214345. Sequence in context: A130098 A046123 A152292 * A039319 A043142 A043922 Adjacent sequences:  A214490 A214491 A214492 * A214494 A214495 A214496 KEYWORD nonn,easy AUTHOR Yasir Karamelghani Gasmallah, Jul 19 2012 STATUS approved

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Last modified December 15 11:43 EST 2019. Contains 329999 sequences. (Running on oeis4.)