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Triangle of coefficients of representations of columns of A213745 in binomial basis.
2

%I #14 Feb 13 2013 23:58:31

%S 1,0,1,0,1,1,0,1,2,1,0,1,3,3,1,0,1,4,6,4,1,0,1,5,10,10,5,1,0,0,6,15,

%T 20,15,6,1,0,0,5,21,35,35,21,7,1,0,0,4,25,56,70,56,28,8,1,0,0,3,27,80,

%U 126,126,84,36,9,1

%N Triangle of coefficients of representations of columns of A213745 in binomial basis.

%C This array is the fifth array in the sequence of arrays A026729, A071675, A213887, A213888,..., such that the first two arrays are considered as triangles.

%C Let {a_(k,i)}, k>=1, i=0,...,k, be the k-th row of the triangle. Then s_k(n)=sum{i=0,...,k}a_(k,i)* binomial(n,k) is the n-th element of the k-th column of A213745. For example, s_1(n)=binomial(n,1)=n is the first column of A213745 for n>1, s_2(n)=binomial(n,1)+binomial(n,2)is the second column of A213745 for n>1, etc. In particular (see comment in A213745), in cases k=8,9 s_k(n) is A063417(n+2), A063418(n+2) respectively.

%e As a triangle, this begins

%e n/k.|..0....1....2....3....4....5....6....7....8....9

%e =====================================================

%e .0..|..1

%e .1..|..0....1

%e .2..|..0....1....1

%e .3..|..0....1....2....1

%e .4..|..0....1....3....3....1

%e .5..|..0....1....4....6....4....1

%e .6..|..0....1....5...10...10....5....1

%e .7..|..0....0....6...15...20...15....6....1

%e .8..|..0....0....5...21...35...35...21....7....1

%e .9..|..0....0....4...25...56...70...56...28....8....1

%Y Cf. A026729, A071675, A213887, A213888.

%K nonn,tabl

%O 0,9

%A _Vladimir Shevelev_ and _Peter J. C. Moses_, Jun 23 2012