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A213660
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Irregular triangle read by rows: T(n,k) is the number of dominating subsets with k vertices of the graph G(n) obtained by taking n copies of the cycle graph C_3 with a vertex in common.
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0
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3, 3, 1, 1, 8, 10, 5, 1, 1, 6, 23, 32, 21, 7, 1, 1, 8, 28, 72, 102, 80, 36, 9, 1, 1, 10, 45, 120, 242, 332, 290, 160, 55, 11, 1, 1, 12, 66, 220, 495, 856, 1116, 1032, 655, 280, 78, 13, 1, 1, 14, 91, 364, 1001, 2002, 3131, 3880, 3675, 2562, 1281, 448, 105, 15, 1
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OFFSET
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1,1
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COMMENTS
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Row n contain 2n + 1 entries.
Sum of entries in row n = 3^n + 4^n = A074605(n).
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LINKS
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FORMULA
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Generating polynomial of row n is x*(1+x)^(2*n) + (2*x+x^2)^n; this is the domination polynomial of the graph G(n).
T(n,k) = 2^(2*n-k)*binomial(n,k-n) + binomial(2*n,k-1) (n >= 1; 1 <= k <= 2*n+1).
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EXAMPLE
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Row 1 is 3,3,1 because the graph G(1) is the triangle abc; there are 3 dominating subsets of size 1 ({a}, {b}, {c}), 3 dominating subsets of size 2 ({a,b}, {a,c}, {b,c}), and 1 dominating subset of size 3 ({a,b,c}).
T(n,1)=1 for n >= 2 because the common vertex of the triangles is the only dominating subset of size k=1.
Triangle starts:
3, 3, 1;
1, 8, 10, 5, 1;
1, 6, 23, 32, 21, 7, 1;
1, 8, 28, 72, 102, 80, 36, 9, 1;
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MAPLE
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T := proc (n, k) options operator, arrow: 2^(2*n-k)*binomial(n, k-n)+binomial(2*n, k-1) end proc: for n to 9 do seq(T(n, k), k = 1 .. 2*n+1) end do; # yields sequence in triangular form
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MATHEMATICA
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T[n_, k_] := 2^(2n-k) Binomial[n, k-n] + Binomial[2n, k-1];
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PROG
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(Magma) /* As triangle */ [[2^(2*n-k)*Binomial(n, k-n)+Binomial(2*n, k-1): k in [1..2*n+1]]: n in [1.. 10]]; // Vincenzo Librandi, Jul 20 2019
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CROSSREFS
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KEYWORD
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nonn,tabf
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AUTHOR
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STATUS
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approved
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