OFFSET
0,2
COMMENTS
a(9k) = 0 for all k>1.
I conjecture that all terms > 278, except for 10001, end in the digit "9". What is the next term a(n) > 69 violating monotony, i.e., such that a(n) < a(n-1)? M. F. Hasler, Jun 17 2012
a(88) = 7999999999 < a(87) = 8899899999. - Alois P. Heinz, Jun 17 2012
a(76) = 499999999 < a(75) = 597999999. - Donovan Johnson, Jun 18 2012
LINKS
Alois P. Heinz, Table of n, a(n) for n = 0..400 (first 101 terms from Donovan Johnson)
MATHEMATICA
semiPrimeQ[n_] := PrimeOmega[n] == 2; t = Table[0, {100}]; k = 1; While[k < 10^7, If[ semiPrimeQ@ k, s = Plus @@ IntegerDigits@ k; If[s < 101 && t[[s]] == 0, t[[s]] = k; Print[{s, k}]]]; k++]
PROG
(PARI) A213653(n)={ n%9 || n==9 || return; forstep( a=A051885(n), 9e9, 9, bigomega(a)==2 || next; A007953(a)==n & return(a))} \\ - M. F. Hasler, Jun 17 2012
CROSSREFS
KEYWORD
easy,base,nonn
AUTHOR
Robert G. Wilson v, Jun 17 2012
EXTENSIONS
a(0)-a(62) double-checked with given PARI code by M. F. Hasler, Jun 17 2012
STATUS
approved