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%I #5 May 10 2012 13:19:43
%S 1,1,7,110,2875,109683,5678706,380631612,31942104109,3272150145947,
%T 401101904099311,57890233456712428,9706532459502104648,
%U 1869487973632573739154,409621529316840179292622,101253590975320030584465534,28030292175164530782257192631
%N Self-convolution yields A212370.
%C A212370 satisfies: 1 = Sum_{n>=0} A212370(n)*x^n*[Sum_{k=0..n+1} binomial(n+1, k)^2*(-x)^k]^2.
%e G.f.: A(x) = 1 + x + 7*x^2 + 110*x^3 + 2875*x^4 + 109683*x^5 +...
%e such that
%e A(x)^2 = 1 + 2*x + 15*x^2 + 234*x^3 + 6019*x^4 + 226656*x^5 +...+ A212370(n)*x^n +...
%Y Cf. A212370.
%K nonn
%O 0,3
%A _Paul D. Hanna_, May 10 2012
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