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A212283
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First a(n) > 1 whose sum of digits is the same in base 2 as in base n.
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1
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2, 6, 4, 6, 12, 21, 8, 10, 20, 12, 14, 172, 30, 46, 16, 18, 36, 20, 22, 126, 46, 24, 26, 126, 28, 30, 58, 60, 120, 126, 32, 34, 68, 36, 38, 185, 78, 40, 42, 126, 44, 46, 90, 92, 138, 48, 50, 246, 52, 54, 106, 108, 56, 58, 114, 60, 62, 120, 182, 126, 188, 378
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OFFSET
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2,1
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COMMENTS
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Theoretically, there might exist an n for which there is no solution, in which case a(n) would be set to 0 by convention; however, no such case was found so far. Problem: does it exist?
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LINKS
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EXAMPLE
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Example: a(13) = 172 because 172 is the first number >1 such that its expansions in base 2 (10101100) and in base 13 (103) have the same sum of digits, namely 4.
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MATHEMATICA
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sdn[n_]:=Module[{a=2}, While[Total[IntegerDigits[a, 2]]!=Total[ IntegerDigits[ a, n]], a++]; a]; Array[sdn, 70, 2] (* Harvey P. Dale, May 29 2013 *)
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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