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A211957
Triangle of coefficients of a polynomial sequence related to the Morgan-Voyce polynomials A085478.
4
1, 1, 1, 1, 4, 2, 1, 9, 12, 4, 1, 16, 40, 32, 8, 1, 25, 100, 140, 80, 16, 1, 36, 210, 448, 432, 192, 32, 1, 49, 392, 1176, 1680, 1232, 448, 64, 1, 64, 672, 2688, 5280, 5632, 3328, 1024, 128, 1, 81, 1080, 5544, 14256, 20592, 17472, 8640, 2304, 256, 1, 100, 1650, 10560, 34320, 64064, 72800, 51200, 21760, 5120, 512
OFFSET
0,5
COMMENTS
Triangle formed from the even numbered rows of A211956.
The coefficients of the Morgan-Voyce polynomials b(n,x) := sum {k = 0..n} binomial(n+k,2*k)*x^k are listed in A085478. The rational functions 1/2*(b(2*n,2*x) + 1)/b(n,2*x) turn out to be integer polynomials. Their coefficients are listed in this triangle. These polynomials occur as factors of the row polynomials R(n,x) of A211955.
This triangle appears to be the row reverse of the unsigned triangle |A204021|.
FORMULA
T(n,0) = 1 and for k > 0, T(n,k) = n/k*2^(k-1)*binomial(n+k-1,2*k-1) = 2^(k-1)*A208513(n,k).
O.g.f.: ((1-t)-t*x)/((1-t)^2-2*t*x) = 1 + (1+x)*t + (1+4*x+2*x^2)*t^2 + ....
n-th row polynomial R(n,x) = 1/2*(b(2*n,2*x) + 1)/b(n,2*x) = T(2*n,u), where u = sqrt((x+2)/2) and T(n,u) denotes the Chebyshev polynomial of the first kind.
T(n,k) = 2*T(n-1,k)+2*T(n-1,k-1)-T(n-2,k), T(0,0)=T(1,0)=T(1,1)=1, T(n,k)=0 if k<0 or if k>n. - Philippe Deléham, Nov 16 2013
EXAMPLE
Triangle begins
.n\k.|..0....1....2....3....4....5....6....7
= = = = = = = = = = = = = = = = = = = = = = =
..0..|..1
..1..|..1....1
..2..|..1....4....2
..3..|..1....9...12....4
..4..|..1...16...40...32....8
..5..|..1...25..100..140...80...16
..6..|..1...36..210..448..432..192...32
..7..|..1...49..392.1176.1680.1232..448...64
KEYWORD
nonn,easy,tabl
AUTHOR
Peter Bala, Apr 30 2012
STATUS
approved