login
A210991
Total area of the shadows of the three views of the shell model of partitions with n regions.
6
0, 3, 9, 18, 21, 35, 39, 58, 61, 67, 71, 99, 103, 110, 115, 152, 155, 161, 165, 175, 181, 186, 238, 242, 249, 254, 265, 269, 277, 283, 352, 355, 361, 365, 375, 381, 386, 401, 406, 415, 422, 428, 522, 526, 533, 538, 549, 553, 561, 567, 584, 590, 595, 606
OFFSET
0,2
COMMENTS
It appears that if n is a partition number A000041 then the rotated structure with n regions shows each row as a partition of k such that A000041(k) = n (see example).
For the definition of "regions of n" see A206437.
FORMULA
a(n) = A182181(n) + A182727(n) + A210692(n).
a(A000041(n)) = 2*A006128(n) + A026905(n).
EXAMPLE
For n = 11 the three views of the shell model of partitions with 11 regions look like this:
.
. A182181(11) = 35 A210692(11) = 29
.
. 1 1
. 1 1
. 1 1
. 1 1
. 1 1 1 1
. 1 1 1 1
. 1 1 1 1 1 1
. 2 1 1 1 1 2
. 2 1 1 1 1 1 1 2
. 3 2 2 2 1 1 1 1 2 2 3
. 6 3 4 2 5 3 4 2 3 2 1 1 2 3 4 5 6
. <------- Regions ------ ------------> N
. L
. a 1
. r * 2
. g * * 3
. e * 2
. s * * * 4
. t * * 3
. * * * * 5
. p * 2
. a * * * 4
. r * * 3
. t * * * * * 6
. s
.
. A182727(11) = 35
.
The areas of the shadows of the three views are A182181(11) = 35, A182727(11) = 35 and A210692(11) = 29, therefore the total area of the three shadows is 35+35+29 = 99, so a(11) = 99.
Since n = 11 is a partition number A000041 we can see that the rotated structure with 11 regions shows each row as a partition of 6 because A000041(6) = 11. See below:
.
. 6
. 3 3
. 4 2
. 2 2 2
. 5 1
. 3 2 1
. 4 1 1
. 2 2 1 1
. 3 1 1 1
. 2 1 1 1 1
. 1 1 1 1 1 1
.
KEYWORD
nonn
AUTHOR
Omar E. Pol, Apr 30 2012
STATUS
approved