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Number of days after Mar 01 00 such that the date written the format MMDDYY (American standard, short) is palindromic.
3

%I #13 Mar 17 2018 04:07:37

%S 589,600,3603,3614,4272,4283,7255,7297,7955,7966,10967,10978,14651,

%T 14662,18333,18344,22017,22028,25699,25710,29383,29394,33066,33077

%N Number of days after Mar 01 00 such that the date written the format MMDDYY (American standard, short) is palindromic.

%C There are exactly 24 such palindromic dates between Jan 1 00 and Dec 31 99 (see b-file for the complete list).

%C See A210895 for the corresponding dates.

%C The reference date Mar 1 00 makes sense, since this result in a sequence which is independent from the leap year / non-leap year property of the reference year '00'.

%H Hieronymus Fischer, <a href="/A210894/b210894.txt">Table of n, a(n) for n = 1..24</a>

%e The first palindromic date in MMDDYY format after 'Jan 01 00' is A210895(1)=101101 (= 'Oct 11 01' = 'Mar 01 00' + 589 days);

%e The third palindromic date in MMDDYY format after 'Jan 01 00' is A210895(3)=11110=011110 (= 'Jan 11 01' = 'Mar 01 00' + 3603 days);

%e The 10th palindromic date in MMDDYY format after 'Jan 01 00' is A210895(10)=122221 (= 'Dec 22 21' = 'Mar 01 00' + 7966 days).

%e The last (24th) palindromic date in MMDDYY format after 'Jan 01 00' is A210895(24)=92290=092290 (= 'Sep 22 90' = 'Mar 01 00' + 33077 days).

%Y Cf. A210883 - A210893, A210895, A106605, A107273, A107275.

%K nonn,base

%O 1,1

%A _Hieronymus Fischer_, Apr 01 2012