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Number of days after Mar 01 00 such that the date written in the format D.M.YY is palindromic.
4

%I #12 Mar 17 2018 00:10:49

%S 315,346,374,405,435,466,496,527,558,619,690,721,749,780,810,841,871,

%T 902,933,994,1065,1124,1155,1185,1216,1246,1277,1308,1369,3968,3999,

%U 4027,4058,4088,4119,4149,4180,4211,4272,4343,4374,4403,4434,4464

%N Number of days after Mar 01 00 such that the date written in the format D.M.YY is palindromic.

%C There are exactly 214 such palindromic dates between Jan 1 00 and Dec 31 99 (see b-file for the complete list).

%C The definition is different from A210889/A210890 in that the palindrome property is evaluated including the dots.

%C See A210892 for the corresponding dates.

%C The reference date Mar 1 00 makes sense, since this definition results in a sequence which is independent from the leap year / non-leap year property of the reference year '00'.

%H Hieronymus Fischer, <a href="/A210891/b210891.txt">Table of n, a(n) for n = 1..214</a>

%e The first palindromic date in D.M.YY format after 'Jan 01 00' is A210892(1)=10101 (='10.1.01'= 'Jan 10 01' = 'Mar 01 00' + 315 days);

%e The 10th palindromic date in D.M.YY format after 'Jan 01 00' is A210892(10)=101101 (='10.11.01'= 'Nov 10 01' = 'Mar 01 00' + 619 days);

%e The 44th palindromic date in D.M.YY format after 'Mar 01 00' is A210892(44)=21512 (='21.5.12'= 'May 21 12' = 'Mar 01 00' + 4464 days);

%e The last (214th) palindromic date in D.M.YY format after 'Mar 01 00' is A210892(214)=291192 (='29.11.92'= 'Nov 29 92' = 'Mar 01 00' + 33876 days).

%Y Cf. A210883 - A210890, A210892 - A210895, A106605, A107273, A107275

%K nonn,base

%O 1,1

%A _Hieronymus Fischer_, Apr 01 2012