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 A208903 The sum over all bitstrings b of length n with at least two runs of the number of runs in b not immediately followed by a longer run. 5
 0, 4, 12, 32, 76, 180, 412, 940, 2108, 4700, 10364, 22716, 49404, 106876, 229884, 492284, 1049596, 2229756, 4720636, 9964540, 20975612, 44046332, 92282876, 192950268, 402669564, 838885372, 1744863228, 3623927804, 7516258300, 15569354748, 32212385788 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS A run is a maximal subsequence of (possibly just one) identical bits. LINKS Vincenzo Librandi, Table of n, a(n) for n = 1..1000 Aruna Gabhe, Problem 11623, Am. Math. Monthly 119 (2012) 161. Index entries for linear recurrences with constant coefficients, signature (5,-6,-6,16,-8). FORMULA a(n) = 2^n * (2 + (n - 1)/2 - (1/2)^(n - 1) - 2 (1 - (1/2)^floor(n/2)) + (1/2)^(floor(n/2) + 1) (1 + (-1)^n)) - 2. a(n) = A208902(n) - 2. a(n) = 5*a(n-1) - 6*a(n-2) - 6*a(n-3) + 16*a(n-4) - 8*a(n-5), a(1) = 0, a(2) = 4, a(3) = 12, a(4) = 32, a(5) = 76. G.f.: (4*x - 8*x^2 - 4*x^3 + 12*x^4)/(1 - 5*x + 6*x^2 + 6*x^3 - 16*x^4 +    8*x^5). EXAMPLE n=3: 101, 010 each have 3; 100, 011 each have 1; 001, 110 each have 2. (000, 111 do not have at least two runs so they do not contribute.) Summing these gives 6+2+4 = 12 so a(3) = 12. MATHEMATICA Table[2^n*(2 + (n-1)/2 - (1/2)^(n-1) - 2*(1 - (1/2)^Floor[n/2]) + (1/2)^(Floor[n/2] + 1) (1 + (-1)^n)) - 2, {n, 1, 40}] LinearRecurrence[{5, -6, -6, 16, -8}, {0, 4, 12, 32, 76}, 40] CROSSREFS Cf. A056453, A208900, A208901, A208902. Sequence in context: A001934 A004403 A084566 * A079769 A107035 A260145 Adjacent sequences:  A208900 A208901 A208902 * A208904 A208905 A208906 KEYWORD nonn,easy AUTHOR David Nacin, Mar 03 2012 STATUS approved

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Last modified August 16 22:14 EDT 2022. Contains 356169 sequences. (Running on oeis4.)