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A208772
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Number of n-bead necklaces labeled with numbers 1..3 not allowing reversal, with no adjacent beads differing by more than 1.
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4
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3, 5, 7, 12, 19, 39, 71, 152, 315, 685, 1479, 3294, 7283, 16359, 36791, 83312, 189123, 431393, 986247, 2262308, 5200851, 11985863, 27676615, 64034954, 148406243, 344507805, 800902879, 1864502926, 4346071603, 10142619039, 23696518919, 55420734752, 129742923475, 304014655205, 712985901943, 1673486556648
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OFFSET
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1,1
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COMMENTS
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Allowing arbitrary differences between the first and last bead gives A215327. [Joerg Arndt, Aug 08 2012]
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LINKS
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FORMULA
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EXAMPLE
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All solutions for n=4:
..1....2....2....2....1....1....1....3....2....1....2....1
..2....2....3....2....1....2....1....3....3....2....2....1
..1....3....2....2....2....3....1....3....3....2....2....1
..2....3....3....3....2....2....1....3....3....2....2....2
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MATHEMATICA
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sn[n_, k_] := 1/n*Sum[ Sum[ EulerPhi[j]*(1 + 2*Cos[i*Pi/(k + 1)])^(n/j), {j, Divisors[n]}], {i, 1, k}]; Table[sn[n, 3], {n, 1, 36}] // FullSimplify (* Jean-François Alcover, Oct 31 2017, after Joerg Arndt *)
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PROG
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(PARI)
/* from the Knopfmacher et al. reference */
default(realprecision, 99); /* using floats */
sn(n, k)=1/n*sum(i=1, k, sumdiv(n, j, eulerphi(j)*(1+2*cos(i*Pi/(k+1)))^(n/j)));
vector(66, n, round(sn(n, 3)) )
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CROSSREFS
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Cf. A215335 (cyclically smooth Lyndon words with 3 colors).
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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