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A207976
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a(1) = 2; for n>1, a(n) = largest integer such that the sequence b(n) = a(n)^(1/n) is decreasing.
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1
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2, 3, 5, 8, 13, 21, 34, 56, 92, 152, 251, 414, 684, 1130, 1867, 3084, 5095, 8418, 13908, 22979, 37966, 62727, 103638, 171232, 282911, 467429, 772292, 1275990, 2108206, 3483204, 5754993, 9508472, 15710018
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OFFSET
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1,1
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COMMENTS
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LINKS
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FORMULA
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a(1) = 2, a(2) = 3; a(n+1) = floor( a(n)^(1+1/n) ) for n > 1.
a(n) = 1 + floor(q^n), where q = lim a(n+1)/a(n) = 1.652213...
a(2) = 3; a(n) = floor( exp( (n/(n-1)) * log a(n-1) ) ) for n > 2.
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MAPLE
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if n = 1 then
2;
elif n = 2 then
3;
else
floor( exp(n/(n-1)*log(procname(n-1))) );
end if;
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PROG
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(PARI) {a(n) = if( n<3, max(1, n+1), floor( exp( log(a(n-1)) * n/(n-1) )))}; /* Michael Somos, Oct 06 2014 */
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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Thomas Ordowski, Feb 20 2012
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STATUS
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approved
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