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 A207480 a(n) = (3/2)*(1+prime(n)) - prime(n+1). 2
 1, 2, 1, 5, 4, 8, 7, 7, 14, 11, 16, 20, 19, 19, 22, 29, 26, 31, 35, 32, 37, 37, 38, 46, 50, 49, 53, 52, 44, 61, 61, 68, 61, 74, 71, 74, 79, 79, 82, 89, 82, 95, 94, 98, 89, 95, 109, 113, 112, 112, 119, 112, 121, 124, 127, 134, 131, 136, 140, 133, 134, 151 (list; graph; refs; listen; history; text; internal format)
 OFFSET 2,2 COMMENTS Conjecture: a(n) > 0 for all n (cf. A062234). Note that a(1) = 3/2 hence offset is 2. There are many cases of two successive terms of the same value, the first case is a(8)=a(9)=7: p(8)=19, p(9)=23, p(10)=29, (3/2)*(1+19) - 23 =(3/2)*(1+23) - 29=7. The first case of 3 equal successive terms is a(691..693)=2588 for corresponding 4 consecutive primes primes p(691..694)= 5189, 5197, 5209, 5227. The first case of 4 equal successive terms is a(12702874..12702878)=15579672 for corresponding 5 consecutive primes primes p(12702874..12702878)= 231159373,231159389,231159413,231159449,231159503. Also of interest are cases with a(n)>a(n-1), e.g., a(27..29): 53, 52, 44 (the general tendency is, of course, increasing a(n) with n). LINKS Zak Seidov, Table of n, a(n) for n = 2..1001 CROSSREFS Cf. A062234. Sequence in context: A010582 A171175 A176053 * A166517 A019473 A056605 Adjacent sequences:  A207477 A207478 A207479 * A207481 A207482 A207483 KEYWORD nonn AUTHOR Zak Seidov, Feb 18 2012 STATUS approved

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