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EXAMPLE
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Let p(n) = prime(n), then
a(1)=3 because 3 is smallest prime = ( 1 modulo p(1)) = 1 mod 2;
a(2)=7 because 2 smallest consecutive primes {7,11}= {1,2} modulo p(2) = {1,2} mod 3;
a(3) = 251 because {251,257,263,269} = {1,2,3,4} modulo p(3)= {1,2,3,4} mod 5;
a(4) = 61223 because {61223,61231,61253,61261,61283,61291} = {1,2,3,4,5,6} modulo p(4) = {1,2,3,4,5,6} mod 7;
n=5: p(n) = 11, prime(1037632211..1037632220) = {23700022897, 23700022909, 23700022921, 23700022933, 23700022967, 23700022979, 23700022991, 23700023003, 23700023059, 23700023093} = {1,2,3,4,5,6,7,8,9,10} mod 11, d={12,12,12,34,12,12,12,56,34}. - Zak Seidov, Jan 05 2013
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