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A204850
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Expansion of f(x)^3 - 9 * x * f(x^9)^3 in powers of x where f() is a Ramanujan theta function.
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2
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1, -6, 0, -5, 0, 0, -7, 0, 0, 0, -18, 0, 0, 0, 0, 11, 0, 0, 0, 0, 0, -13, 0, 0, 0, 0, 0, 0, 30, 0, 0, 0, 0, 0, 0, 0, 17, 0, 0, 0, 0, 0, 0, 0, 0, 19, 0, 0, 0, 0, 0, 0, 0, 0, 0, 42, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, -23, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 25, 0, 0, 0
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OFFSET
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0,2
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COMMENTS
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LINKS
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FORMULA
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Expansion of f(x^3) * a(-x) in powers of x where f() is a Ramanujan theta function and a() is a cubic AGM theta function.
a(n) = b(8*n + 1) where b() is multiplicative with b(2^e) = 0^e, b(3^e) = - (1 + (-1)^e) * 3^(e/2), b(p^e) = (1 + (-1)^e)/2 * p^(e/2) if p == 1, 3 (mod 8), b(p^e) = (1 + (-1)^e)/2 * (-p)^(e/2) if p == 5, 7 (mod 8). - Michael Somos, Jun 19 2015
G.f. is a period 1 Fourier series which satisfies f(-1 / (2304 t)) = -576 (t/i)^(3/2) g(t) where q = exp(2 Pi i t) and g() is the g.f. for A133079.
a(3*n + 2) = a(5*n + 2) = a(5*n + 4) = a(9*n + 4) = a(9*n + 7) = 0. a(3*n) = A133079(n). a(9*n + 1) = -6 * A133089(n). a(25*n + 3) = -5 * a(n). a(n) = (-1)^n * A202394(n).
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EXAMPLE
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G.f. = 1 - 6*x - 5*x^3 - 7*x^6 - 18*x^10 + 11*x^15 - 13*x^21 + 30*x^28 + ...
G.f. = q - 6*q^9 - 5*q^25 - 7*q^49 - 18*q^81 + 11*q^121 - 13*q^169 + ...
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MATHEMATICA
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a[ n_] := With[ {m = Sqrt[8 n + 1]}, If[ IntegerQ@m, m (-1)^(n + Quotient[m, 6]), 0] If[ Divisible[ m, 3], 2, 1]]; (* Michael Somos, Jun 19 2015 *)
a[ n_] := SeriesCoefficient[ QPochhammer[ -x]^3 - 9 x QPochhammer[ -x^9]^3, {x, 0, n}]; (* Michael Somos, Jun 19 2015 *)
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PROG
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(PARI) {a(n) = my(m); if( issquare(8*n + 1, &m), (-1)^(m \ 6 + n) * m * ((m%3 == 0) + 1), 0)};
(PARI) {a(n) = my(A); if( n<0, 0, A = x * O(x^n); polcoeff( eta(-x + A)^3 - 9 * x * eta(-x^9 + A)^3, n))};
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CROSSREFS
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KEYWORD
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sign
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AUTHOR
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STATUS
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approved
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