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A204156 Symmetric matrix based on f(i,j)=max(3i-j, 3j-i), by antidiagonals. 3

%I #5 Mar 30 2012 18:58:07

%S 1,4,4,7,3,7,10,6,6,10,13,9,5,9,13,16,12,8,8,12,16,19,15,11,7,11,15,

%T 19,22,18,14,10,10,14,18,22,25,21,17,13,9,13,17,21,25,28,24,20,16,12,

%U 12,16,20,24,28,31,27,23,19,15,11,15,19,23,27,31,34,30,26,22,18

%N Symmetric matrix based on f(i,j)=max(3i-j, 3j-i), by antidiagonals.

%C A204156 represents the matrix M given by f(i,j)=max(3i-j, 3j-i) for i>=1 and j>=1. See A204157 for characteristic polynomials of principal submatrices of M, with interlacing zeros. See A204016 for a guide to other choices of M.

%e Northwest corner:

%e 1...4...7...10..13

%e 4...3...6...9...12

%e 7...6...5...8...11

%e 10..9...8...7...10

%t f[i_, j_] := -1 + Max[3 i - j, 3 j - i];

%t m[n_] := Table[f[i, j], {i, 1, n}, {j, 1, n}]

%t TableForm[m[8]] (* 8x8 principal submatrix *)

%t Flatten[Table[f[i, n + 1 - i],

%t {n, 1, 15}, {i, 1, n}]] (* A204156 *)

%t p[n_] := CharacteristicPolynomial[m[n], x];

%t c[n_] := CoefficientList[p[n], x]

%t TableForm[Flatten[Table[p[n], {n, 1, 10}]]]

%t Table[c[n], {n, 1, 12}]

%t Flatten[%] (* A204157 *)

%t TableForm[Table[c[n], {n, 1, 10}]]

%Y Cf. A204157, A204016, A202453.

%K nonn,tabl

%O 1,2

%A _Clark Kimberling_, Jan 12 2012

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Last modified April 19 15:11 EDT 2024. Contains 371794 sequences. (Running on oeis4.)