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%I #6 Mar 30 2012 19:00:28
%S 0,1,2,3,4,5,6,7,8,9,11,22,33,111,222,1111,11111,111111,1111111,
%T 11111111,111111111,11111111111,1111111111111111111111,
%U 111111111111111111111111111111111,11111111111111111111111111111111111111111111,1111111111111111111111111111111111111111111111111111111
%N Repdigit numbers such that both the sum and product of the digits is also a repdigit.
%C a(n) = intersection (A201060, A201061).
%e Number 222 is in sequence because 2*2*2=8, 2+2+2=6; numbers 6 and 8 are both repdigit numbers.
%Y Cf. A201060 (repdigit numbers with repdigit digital product). A201061 (repdigit numbers with repdigit digital sum).
%K nonn,base
%O 1,3
%A _Jaroslav Krizek_, Nov 26 2011