OFFSET
1,1
COMMENTS
Row 5 of A200785.
LINKS
R. H. Hardin, Table of n, a(n) for n = 1..137
FORMULA
Empirical: a(n) = (2017/5040)*n^7 + (1427/360)*n^6 + (5759/360)*n^5 + (607/18)*n^4 + (28459/720)*n^3 + (9113/360)*n^2 + (848/105)*n + 1.
Conjectures from Colin Barker, Oct 15 2017: (Start)
The formulas below are consistent with the conjectured formula above.
G.f.: x*(128 + 767*x + 960*x^2 + 123*x^3 + 60*x^4 - 28*x^5 + 8*x^6 - x^7) / (1 - x)^8.
a(n) = (5040 + 40704*n + 127582*n^2 + 199213*n^3 + 169960*n^4 + 80626*n^5 + 19978*n^6 + 2017*n^7) / 5040.
a(n) = 8*a(n-1) - 28*a(n-2) + 56*a(n-3) - 70*a(n-4) + 56*a(n-5) - 28*a(n-6) + 8*a(n-7) - a(n-8) for n>8.
(End)
EXAMPLE
Some solutions for n=3
..1....0....2....0....0....3....0....1....0....2....2....2....0....3....1....0
..2....2....3....0....2....3....3....1....3....2....0....2....2....1....3....3
..0....0....3....1....2....2....0....0....2....0....0....2....0....1....3....2
..1....1....0....1....3....1....1....0....3....2....3....0....0....0....2....1
..0....1....3....0....1....3....0....0....1....1....2....3....2....3....0....0
..1....3....0....0....1....3....0....1....1....3....3....2....2....0....2....0
..1....1....0....2....1....1....0....0....3....0....0....2....0....2....1....3
CROSSREFS
KEYWORD
nonn
AUTHOR
R. H. Hardin, Nov 22 2011
STATUS
approved