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A200649 Number of 1's in the Stolarsky representation of n. 10
0, 1, 2, 1, 3, 2, 2, 4, 1, 3, 3, 3, 5, 2, 2, 4, 2, 4, 4, 4, 6, 1, 3, 3, 3, 5, 3, 3, 5, 3, 5, 5, 5, 7, 2, 2, 4, 2, 4, 4, 4, 6, 2, 4, 4, 4, 6, 4, 4, 6, 4, 6, 6, 6, 8, 1, 3, 3, 3, 5, 3, 3, 5, 3, 5, 5, 5, 7, 3, 3, 5, 3, 5, 5, 5, 7, 3, 5, 5, 5, 7, 5, 5, 7, 5, 7, 7 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,3
COMMENTS
For the Stolarsky representation of n, see the C. Mongoven link.
LINKS
FORMULA
a(n) = a(n - A130312(n-1)) + (A072649(n-1) - A072649(n - A130312(n-1) - 1)) mod 2 for n > 2 with a(1) = 0, a(2) = 1. - Mikhail Kurkov, Oct 19 2021 [verification needed]
a(n) = A200648(n) - A200650(n). - Amiram Eldar, Jul 07 2023
EXAMPLE
The Stolarsky representation of 19 is 11101. This has 4 1's. So a(19) = 4.
MATHEMATICA
stol[n_] := stol[n] = If[n == 1, {}, If[n != Round[Round[n/GoldenRatio]*GoldenRatio], Join[stol[Floor[n/GoldenRatio^2] + 1], {0}], Join[stol[Round[n/GoldenRatio]], {1}]]];
a[n_] := Count[stol[n], 1]; Array[a, 100] (* Amiram Eldar, Jul 07 2023 *)
PROG
(PARI) stol(n) = {my(phi=quadgen(5)); if(n==1, [], if(n != round(round(n/phi)*phi), concat(stol(floor(n/phi^2) + 1), [0]), concat(stol(round(n/phi)), [1]))); }
a(n) = vecsum(stol(n)); \\ Amiram Eldar, Jul 07 2023
CROSSREFS
Sequence in context: A199246 A367858 A363718 * A298742 A086415 A069013
KEYWORD
nonn,base,changed
AUTHOR
Casey Mongoven, Nov 19 2011
EXTENSIONS
More terms from Amiram Eldar, Jul 07 2023
STATUS
approved

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Last modified April 24 22:17 EDT 2024. Contains 371964 sequences. (Running on oeis4.)