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a(n) = 6*11^n + 1.
1

%I #15 Mar 17 2023 14:42:41

%S 7,67,727,7987,87847,966307,10629367,116923027,1286153287,14147686147,

%T 155624547607,1711870023667,18830570260327,207136272863587,

%U 2278499001499447,25063489016493907,275698379181432967,3032682170995762627

%N a(n) = 6*11^n + 1.

%H Vincenzo Librandi, <a href="/A199756/b199756.txt">Table of n, a(n) for n = 0..900</a>

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (12,-11).

%F a(n) = 11*a(n-1)-10.

%F a(n) = 12*a(n-1)-11*a(n-2).

%F G.f.: (7-17*x)/((1-x)*(1-11*x)).

%t 6*11^Range[0,20]+1 (* or *) LinearRecurrence[{12,-11},{7,67},20] (* _Harvey P. Dale_, Jul 16 2014 *)

%o (Magma) [6*11^n+1: n in [0..30]];

%K nonn,easy

%O 0,1

%A _Vincenzo Librandi_, Nov 10 2011