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a(n) = 7*4^n+1.
3

%I #19 Mar 20 2023 11:53:08

%S 8,29,113,449,1793,7169,28673,114689,458753,1835009,7340033,29360129,

%T 117440513,469762049,1879048193,7516192769,30064771073,120259084289,

%U 481036337153,1924145348609,7696581394433,30786325577729

%N a(n) = 7*4^n+1.

%H Vincenzo Librandi, <a href="/A199207/b199207.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (5,-4).

%F a(n) = 4*a(n-1)-3.

%F a(n) = 5*a(n-1)-4*a(n-2).

%F G.f.: (8-11*x)/((1-x)*(1-4*x)). - _Bruno Berselli_, Nov 04 2011

%t 7*4^Range[0,30]+1 (* or *) LinearRecurrence[{5,-4},{8,29},30] (* _Harvey P. Dale_, Jan 21 2023 *)

%o (Magma) [7*4^n+1: n in [0..30]];

%K nonn,easy

%O 0,1

%A _Vincenzo Librandi_, Nov 04 2011