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%I #10 Oct 30 2018 10:31:02
%S 1,1,2,26,53,365,73,13369,31226,40193,1346393,10982633,59784881,
%T 12459674,197301737,4044371993,16335212753,165277755905,33055551181,
%U 627510050434,2556360882389,25830314642530,5166062928506,433477841994649,1561599571802482
%N a(n) = (1+(A034939(n))^2)/5^n.
%H Zak Seidov, <a href="/A199206/b199206.txt">Table of n, a(n) for n = 0..100</a>
%e a(0)=(1+(A034939(0))^2)/5^0=(1+(0)^2)/1=1,
%e a(1)=(1+(A034939(1))^2)/5^1=(1+(2)^2)/5=1,
%e a(2)=(1+(A034939(2))^2)/5^2=(1+(7)^2)/25=2,
%e a(3)=(1+(A034939(3))^2)/5^3=(1+(57)^2)/5^3=3250/125=26.
%Y Cf. A034939.
%K nonn
%O 0,3
%A _Zak Seidov_, Nov 04 2011
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