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(5*11^n-1)/2.
1

%I #17 Sep 08 2022 08:46:00

%S 2,27,302,3327,36602,402627,4428902,48717927,535897202,5894869227,

%T 64843561502,713279176527,7846070941802,86306780359827,

%U 949374583958102,10443120423539127,114874324658930402,1263617571248234427

%N (5*11^n-1)/2.

%H Vincenzo Librandi, <a href="/A199021/b199021.txt">Table of n, a(n) for n = 0..900</a>

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (12,-11).

%F a(n) = 11*a(n-1)+5.

%F a(n) = 12*a(n-1)-11*a(n-2), n>1.

%F G.f.: (2 + 3*x)/(1 - 12*x + 11*x^2). - _Vincenzo Librandi_, Jan 04 2013

%t CoefficientList[Series[(2 + 3*x)/(1 - 12*x + 11*x^2), {x, 0, 30}], x] (* _Vincenzo Librandi_, Jan 04 2013 *)

%t LinearRecurrence[{12,-11},{2,27},20] (* _Harvey P. Dale_, Aug 13 2018 *)

%o (Magma) [(5*11^n-1)/2 : n in [0..20]]

%K nonn,easy

%O 0,1

%A _Vincenzo Librandi_, Nov 02 2011