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A198680 Multiples of 3 whose sum of base-3 digits are also multiples of 3. 5
0, 15, 21, 33, 39, 45, 57, 63, 78, 87, 93, 99, 111, 117, 132, 135, 150, 156, 165, 171, 186, 189, 204, 210, 222, 228, 234, 249, 255, 261, 273, 279, 294, 297, 312, 318, 327, 333, 348, 351, 366, 372, 384, 390, 396, 405, 420, 426, 438, 444, 450, 462, 468, 483, 489, 495 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,2

COMMENTS

It appears that Sum[k^j, 0<=k<=2^n-1, k in A198680] = Sum[k^j, 0<=k<=2^n-1, k in A198681] = Sum[k^j, 0<=k<=2^n-1, k in A180682], for 0<=j<=n-1, which has been verified numerically in a number of cases. This is a generalization of Prouhet's Theorem (see the reference).  To illustrate for j=3, we have  Sum[k^3, 0<=k<=2^n-1, k in A198680] = {0, 0, 12636, 1108809, 94478400, 7780827681, 633724260624, 51425722195929, 4168024588857600,...}, Sum[k^3, 0<=k<=2^n-1, k in A198681] =  {0, 27, 14580, 1095687, 94478400, 7780827681, 633724260624, 51425722195929, 4168024588857600,..., Sum[k^3, 0<=k<=2^n-1, k in A198682] = {0, 216, 7776, 1121931, 94478400, 7780827681, 633724260624, 51425722195929, 4168024588857600,...}, and it is seen that all three sums agree for n>=4=j+1.

REFERENCES

Chris Bernhardt, "Evil Twins Alternate with Odious Twins", Math. Mag. 82 (2009) 57-62.

LINKS

Table of n, a(n) for n=0..55.

Eric Weisstein's World of Mathematics, Prouhet-Tarry-Escott Problem

FORMULA

a(n) = 3*A079498(n). [Charles R Greathouse IV, Nov 02 2011]

CROSSREFS

Cf. A000069, A001969, A157971, A15870, A198681, A198682.

Sequence in context: A225709 A020162 A046404 * A177516 A214044 A127329

Adjacent sequences:  A198677 A198678 A198679 * A198681 A198682 A198683

KEYWORD

nonn,easy,base

AUTHOR

John W. Layman, Oct 28 2011

STATUS

approved

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Last modified June 19 11:03 EDT 2013. Contains 226404 sequences.