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a(n) = round((n+1/4)^n).
1

%I #12 Sep 08 2022 08:45:59

%S 1,5,34,326,3988,59605,1052849,21460092,495764693,12800845442,

%T 365323615365,11419131242071,387977390372850,14236659589753581,

%U 561109543344974894,23640346895461300427,1060265646084471617079,50434955069054663240727

%N a(n) = round((n+1/4)^n).

%H Vincenzo Librandi, <a href="/A198078/b198078.txt">Table of n, a(n) for n = 1..300</a>

%t Table[Round[(n + 1/4)^n], {n, 20}] (* _Wesley Ivan Hurt_, Jun 22 2022 *)

%o (Magma) [Round((n+1/4)^n): n in [1..20]]

%Y Cf. A014056, A197714.

%K nonn

%O 1,2

%A _Vincenzo Librandi_, Oct 21 2011