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a(n) = ceiling((3n+1/n)^n).
6

%I #15 Mar 04 2023 16:44:59

%S 4,43,814,22519,811369,35946076,1888624972,114746269758,7912720985080,

%T 610470884770407,52094956940751711,4871691779130290167,

%U 495409898474358881327,54427906182810588386674,6424384909407981686846706,810777549111969648699638307,108944087230453697240059783284

%N a(n) = ceiling((3n+1/n)^n).

%H Vincenzo Librandi, <a href="/A197717/b197717.txt">Table of n, a(n) for n = 1..300</a>

%t Table[Ceiling[(3n+1/n)^n],{n,20}] (* _Harvey P. Dale_, Mar 04 2023 *)

%o (Magma) [Ceiling((3*n+1/n)^n): n in [1..20]]

%o (PARI) a(n)=ceil((3*n+1/n)^n) \\ _Charles R Greathouse IV_, Nov 21 2011

%Y Cf. A014058.

%K nonn,less

%O 1,1

%A _Vincenzo Librandi_, Oct 18 2011