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a(n) = floor((n+1/2)^n).
1

%I #11 Sep 08 2022 08:45:59

%S 1,6,42,410,5032,75418,1334838,27249052,630249409,16288946267,

%T 465239139606,14551915228366,494696673952511,18161513224841275,

%U 716102966059713315,30181658957863752409,1354087807629298185929,64430442087414935111821,3240840189607299761533535,171821387249394349577932210

%N a(n) = floor((n+1/2)^n).

%H Vincenzo Librandi, <a href="/A197712/b197712.txt">Table of n, a(n) for n = 1..300</a>

%p A197712:=n->floor((n+1/2)^n): seq(A197712(n), n=1..25); # _Wesley Ivan Hurt_, Apr 18 2017

%t Table[Floor[(n+1/2)^n],{n,30}] (* _Harvey P. Dale_, Nov 15 2013 *)

%o (Magma) [Floor((n+1/2)^n): n in [1..20]]

%Y Cf. A014052.

%K nonn,easy

%O 1,2

%A _Vincenzo Librandi_, Oct 18 2011