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a(n) = floor((4*n+1/n)^n).
2

%I #14 Dec 31 2023 15:56:04

%S 5,72,1876,69729,3363232,199205126,13982257728,1134344816184,

%T 104416147080711,10750872867074586,1224163955433850943,

%U 152733676280699540998,20719969553916698313304,3036565789908881887393113,478082645334119488823777214,80475210949356295594385157620

%N a(n) = floor((4*n+1/n)^n).

%H Vincenzo Librandi, <a href="/A197324/b197324.txt">Table of n, a(n) for n = 1..300</a>

%t Table[Floor[(4n+1/n)^n],{n,20}] (* _Harvey P. Dale_, Mar 23 2012 *)

%o (Magma) [Floor((4*n+1/n)^n): n in [1..20]]

%o (PARI) a(n)=floor((4*n+1/n)^n) \\ _Charles R Greathouse IV_, Dec 27 2011

%Y Cf. A014052.

%K nonn,less

%O 1,1

%A _Vincenzo Librandi_, Oct 17 2011