

A197099


Define the array k(n,x) = number of m such that tau(gcd(n,m)) is x where m runs from 1 to n. Also define h(n,x) = Sum_{dn : tau(d) = x} d. The sequence contains numbers n such that k(n,x)*x = h(n,x) has at least one solution x.


0



1, 2, 4, 32, 48, 180, 189, 224, 288, 360, 432, 1280, 1344, 1536, 1600, 4096, 28672, 46656, 54000, 108000, 131220, 150528, 225792, 262440, 405450, 442800, 525312, 532480, 590400, 594000, 630784, 633600, 655360, 792000, 819200, 885600, 950400
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OFFSET

1,2


COMMENTS

In the definition tau=A000005. By construction of the two arrays, their row sums and/or first moments are sum_{x=1..z} k(x)*x = sum_{x=1..z} h(x) = sigma(n) =A000203(n).
Comment from R. J. Mathar, Oct 12 2011:
The table k(n,x) with row sums n is a frequency distribution of tau which starts in row n=1 with columns x>=1 as follows:
1,0,0,0,0,0,0,0,..
1,1,0,0,0,0,0,0,..
2,1,0,0,0,0,0,0,..
2,1,1,0,0,0,0,0,..
4,1,0,0,0,0,0,0,..
2,3,0,1,0,0,0,0,..
6,1,0,0,0,0,0,0,..
4,2,1,1,0,0,0,0,..
6,2,1,0,0,0,0,0,..
4,5,0,1,0,0,0,0,..
10,1,0,0,0,0,0,0,..
4,4,2,1,0,1,0,0,..
By multiplying with the column number x we obtain another array x*k(n,x) which has row sums sigma(n):
1,0,0,0,0,0,0,0,..
1,2,0,0,0,0,0,0,..
2,2,0,0,0,0,0,0,..
2,2,3,0,0,0,0,0..
4,2,0,0,0,0,0,0,..
2,6,0,4,0,0,0,0,..
6,2,0,0,0,0,0,0,..
4,4,3,4,0,0,0,0,..
6,4,3,0,0,0,0,0,..
4,10,0,4,0,0,0,0,..
10,2,0,0,0,0,0,0,..
4,8,6,4,0,6,0,0,..
The array h(n,x) with another frequency distribution of tau and also rows sums sigma(n) starts in row n=1 as follows:
1,0,0,0,0,0,0,0,..
1,2,0,0,0,0,0,0,..
1,3,0,0,0,0,0,0,..
1,2,4,0,0,0,0,0,..
1,5,0,0,0,0,0,0,..
1,5,0,6,0,0,0,0,..
1,7,0,0,0,0,0,0,..
1,2,4,8,0,0,0,0,..
1,3,9,0,0,0,0,0,..
1,7,0,10,0,0,0,0,..
1,11,0,0,0,0,0,0,..
1,5,4,6,0,12,0,0,..
Whenever the previous two tables match at one position (n,x) for a nonzero entry, we add the corresponding row number n to the sequence. The rows at n=4, (2,2,3) and (1,2,4) for example, match at x=2, which adds n=4 to the sequence. (End)


LINKS

Table of n, a(n) for n=1..37.


EXAMPLE

For n = 189 ; 21189, 27189 and tau(21) = tau(27) = 4 ; h(4) = Sum_{d189; tau(d) = 4} d = 21+27 = k(4)*4 = 12*4 = 48. Therefore 189 is in the sequence.


MAPLE

k := proc(n, x)
a := 0 ;
for m from 1 to n do
if numtheory[tau](igcd(n, m)) = x then
a := a+1 ;
end if;
end do;
a ;
end proc:
h := proc(n, x)
a := 0 ;
for d in numtheory[divisors](n) do
if numtheory[tau](d) = x then
a := a+d ;
end if;
end do;
a ;
end proc:
isA197099 := proc(n)
for x from 1 to n do
if h(n, x) = x*k(n, x) and h(n, x) <> 0 then
return true;
end if;
end do:
false;
end proc:
for n from 1 do
if isA197099(n) then
print(n);
end if;
end do: # R. J. Mathar, Oct 12 2011


PROG

(Sage)
def is_A197099(n): # extremely inefficient but useful for reference purposes
....k = lambda x: sum(1 for m in (1..n) if number_of_divisors(gcd(n, m))==x)
....h = lambda x: sum(d for d in divisors(n) if number_of_divisors(d)==x)
....return any(h(x) != 0 and h(x) % x == 0 and h(x) == x*k(x) for x in (1..n)) # [D. S. McNeil, Oct 12 2011]


CROSSREFS

Sequence in context: A019542 A293760 A101575 * A009098 A192387 A133127
Adjacent sequences: A197096 A197097 A197098 * A197100 A197101 A197102


KEYWORD

nonn


AUTHOR

Naohiro Nomoto, Oct 10 2011


STATUS

approved



