OFFSET
1,2
COMMENTS
Determinant of the n X n matrix with consecutive Lucas numbers along the main diagonal, and 1's everywhere else.
Log(a(n))/n^2 approaches a constant (approximately 0.24) as n approaches infinity.
This limit is equal to log(phi)/2 = 0.24060591252980172374887945671218421156759..., where phi = A001622 = (1+sqrt(5))/2 is the golden ratio. - Vaclav Kotesovec, Apr 10 2016
FORMULA
prod(F(k)+F(k+2)-1, k=1..n-1), where F(k) is the k-th Fibonacci number.
a(n) ~ c * phi^(n*(n+1)/2), where phi = A001622 = (1+sqrt(5))/2 is the golden ratio and c = 0.22805409619361969822736866017363184926893729185052240813641180656087... . - Vaclav Kotesovec, Apr 10 2016
MATHEMATICA
Table[Det[Array[1+(LucasL[#1]-1)*KroneckerDelta[#1, #2]&, {n, n}]], {n, 30}] (* or *)
Table[Product[Fibonacci[k]+Fibonacci[k+2]-1, {k, 1, n-1}], {n, 30}] (* or *)
RecurrenceTable[{a[n+1]==(Fibonacci[n]+Fibonacci[n+2]-1) a[n], a[1] == 1}, a, {n, 30}]
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
John M. Campbell, Oct 06 2011
STATUS
approved