login
G.f. A(x) satisfies: A(x)^2 + A(-x)^2 = 2 and A(x)^3 - A(-x)^3 = 36*x.
5

%I #7 Apr 04 2022 19:50:28

%S 1,6,-18,144,-1026,10368,-91044,995328,-9630090,109486080,-1120744188,

%T 13042778112,-138540597588,1637370298368,-17853248637000,

%U 213325958873088,-2371846639850586,28573129903177728,-322526246042905740,3910007249908531200,-44670671340291807228

%N G.f. A(x) satisfies: A(x)^2 + A(-x)^2 = 2 and A(x)^3 - A(-x)^3 = 36*x.

%F From _Paul D. Hanna_, Apr 04 2022: (Start)

%F a(2*n+1) = 6 * 24^n * binomial(3*n+1,n)/(3*n+1) for n >= 0.

%F G.f. A(x) = Sum_{n>=0} a(n)*x^n satisfies:

%F (1) (A(x)^2 + A(-x)^2)/2 = 1.

%F (2) (A(x)^3 - A(-x)^3)/2 = 18*x.

%F (3) (A(x) - A(-x))/2 = 6*Series_Reversion(x - 24*x^3).

%F (4) (A(x) + A(-x))/2 = sqrt( (1 + A(x)*A(-x))/2 ).

%F (5) A(x)*A(-x) = 1 - 72*Series_Reversion(x - 24*x^3)^2.

%F (6) A(x) = B(x) + sqrt(1 - B(x)^2), where B(x) = 6*Series_Reversion(x - 24*x^3).

%F (End)

%e G.f.: A(x) = 1 + 6*x - 18*x^2 + 144*x^3 - 1026*x^4 + 10368*x^5 +...

%e where

%e A(x)^2 = 1 + 12*x + 72*x^3 + 3240*x^5 + 229392*x^7 + 20083464*x^9 +...

%e A(x)^3 = 1 + 18*x + 54*x^2 + 1134*x^4 + 63180*x^6 + 4903254*x^8 +...

%o (PARI) {a(n)=local(A=[1,6]);for(k=2,n,A=concat(A,0);if(k%2==0,A[#A]=-Vec(Ser(A)^2)[#A]/2,A[#A]=-Vec(Ser(A)^3)[#A]/3));A[n+1]}

%o (PARI) /* Using series reversion: */

%o {a(n) = my(A, B = 6*serreverse(x - 24*x^3 +x^2*O(x^n)) );

%o A = B + sqrt(1 - B^2); polcoeff(A,n)}

%o for(n=0,20,print1(a(n),", ")) \\ _Paul D. Hanna_, Apr 04 2022

%Y Cf. A196869, A193618, A193619, A196864, A196865, A196866, A196867.

%K sign

%O 0,2

%A _Paul D. Hanna_, Oct 06 2011