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 A196081 Dungeons and Dragons Ability Modifier Sequence. 1
 10, 0, 11, 0, 12, 1, 13, 1, 14, 2, 15, 2, 16, 3, 17, 3, 18, 4, 19, 4, 20, 5, 21, 5, 22, 6, 23, 6, 24, 7, 25, 7, 26, 8, 27, 8, 28, 9, 29, 9, 30, 10, 31, 10, 32, 11, 33, 11, 34, 12, 35 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,1 REFERENCES Rob Heinsoo and Andy Collins and James Wyatt, Wizards of the Coast, 2008, page 17, Dungeons and Dragons Player's Handbook LINKS Harvey P. Dale, Table of n, a(n) for n = 0..999 Index entries for linear recurrences with constant coefficients, signature (0,1,0,1,0,-1). FORMULA a(n+5) = a(n)+a(n+1)-a(n+4)+3. - Alexander R. Povolotsky, Sep 27 2011 a(n) = 19/4-(1/8*I)*I^n+1/8*(-1)^n*n+21/4*(-1)^n+3/8*n+(1/8*I)*(-I)^n. - Alexander R. Povolotsky, Sep 27 2011 G.f.: ( 10+x^2-9*x^4+x^5 ) / ( (x^2+1)*(x-1)^2*(1+x)^2 ). - R. J. Mathar, Sep 27 2011 a(2n) = n+10. a(2n+1) = A004526(n). a(0)=10, a(1)=0, a(2)=11, a(3)=0, a(4)=12, a(5)=1, a(n)=a(n-2)+a(n-4)- a(n-6). - Harvey P. Dale, Oct 01 2011 MATHEMATICA LinearRecurrence[{0, 1, 0, 1, 0, -1}, {10, 0, 11, 0, 12, 1}, 60] (* or *) CoefficientList[Series[(10+x^2-9x^4+x^5)/((x^2+1)(x-1)^2(1+x)^2), {x, 0, 60}], x] (* Harvey P. Dale, Oct 01 2011 *) PROG (C#) public int Modifier(int score) {int modifier = 0; if (score % 2 == 0) {modifier = score / 2 - 5; } else {modifier = (score -1) / 2 - 5; } return modifier; } CROSSREFS Sequence in context: A095418 A055961 A341504 * A320380 A088001 A344071 Adjacent sequences: A196078 A196079 A196080 * A196082 A196083 A196084 KEYWORD nonn,easy AUTHOR Daniel Ray, Sep 27 2011 STATUS approved

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Last modified January 30 19:55 EST 2023. Contains 359947 sequences. (Running on oeis4.)