OFFSET
0,1
COMMENTS
Obviously T(n,k) = 0 for all odd k.
Conjecture: The polynomials p(n,x) = sum_{k=0..n} T(n,k)*x^(n-k) based on this simple recurrence for other initial constant values of T(0,0)=p and T(1,0)=q are related to the S-polynomials of A053119: p(n,x,p+1,q+1)-p(n,x,p,q) = S(n,x).
EXAMPLE
-2;
3, 0;
3, 0, 2;
3, 0, -1, 0;
3, 0, -4, 0, -2;
3, 0, -7, 0, -1, 0;
3, 0, -10, 0, 3, 0, 2;
3, 0, -13, 0, 10, 0, 3, 0.
CROSSREFS
KEYWORD
AUTHOR
Paul Curtz, Sep 23 2011
STATUS
approved