%I #11 Mar 30 2012 18:39:46
%S 14,89,3104,265832,42711550,11454711984,4840928618302,
%T 3108267243405312,2924919606477510504,3870562086323220000000,
%U 6908112063470228210507358,16038451894952529045493383168,47076979725683125083464370176990,170928617514191160703263296201650176
%N a(n) = 2*n^(2*n)*(1+ sum((1+k^(n+2)/n+k/n)/(n^k*k!), k=1..infinity)) / exp(1/n).
%e n=1: 2*(1+ sum((1+k^3+k)/k!, k=1..infinity))/exp(1) = 14.
%Y Cf. A001113, A092516, A092514, A092041.
%K nonn
%O 1,1
%A _Alexander R. Povolotsky_, Sep 14 2011