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COMMENTS
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Add one to the cube of the previous term, and reverse the digits in base 10 to obtain the next term. a(1)= 1, a(n+1) = A004086(1+A000578(a(n))). This is a flawed try to make the analogue to the exponent 3 as A193914 is to the exponent 2.
The number of digits is 1, 1, 1, 2, 5, 14, 41, 123, 369, 1105,... in the n=1st, 2nd, 3rd etc term.
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