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A194900 Rectangular array, by antidiagonals: row n gives the positions of n in the fractal sequence A194899; an interspersion. 4

%I #5 Mar 30 2012 18:57:44

%S 1,2,3,5,6,4,8,10,7,9,13,15,12,14,11,18,21,17,20,16,19,25,28,24,27,23,

%T 26,22,32,36,31,35,30,34,29,33,41,45,40,44,39,43,38,42,37,50,55,49,54,

%U 48,53,47,52,46,51,61,66,60,65,59,64,58,63,57,62,56,72,78,71

%N Rectangular array, by antidiagonals: row n gives the positions of n in the fractal sequence A194899; an interspersion.

%C See A194832 for a general discussion.

%e Northwest corner:

%e 1...2...5...8...13..18

%e 3...6...10..15..21..28

%e 4...7...12..17..24..31

%e 9...14..20..27..35..44

%e 11..16..23..30..39..48

%t r = Sqrt[12];

%t t[n_] := Table[FractionalPart[k*r], {k, 1, n}];

%t f = Flatten[Table[Flatten[(Position[t[n], #1] &) /@

%t Sort[t[n], Less]], {n, 1, 20}]] (* A194899 *)

%t TableForm[Table[Flatten[(Position[t[n], #1] &) /@

%t Sort[t[n], Less]], {n, 1, 15}]]

%t row[n_] := Position[f, n];

%t u = TableForm[Table[row[n], {n, 1, 20}]]

%t g[n_, k_] := Part[row[n], k];

%t p = Flatten[Table[g[k, n - k + 1], {n, 1, 15},

%t {k, 1, n}]] (* A194900 *)

%t q[n_] := Position[p, n]; Flatten[Table[q[n],

%t {n, 1, 90}]] (* A194901 *)

%Y Cf. A194832, A194899, A194901.

%K nonn,tabl

%O 1,2

%A _Clark Kimberling_, Sep 05 2011

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Last modified April 25 06:49 EDT 2024. Contains 371964 sequences. (Running on oeis4.)