OFFSET
1,1
COMMENTS
FORMULA
EXAMPLE
Triangle begins:
42;
15, 27;
10, 14, 18;
5, 10, 10, 17;
4, 5, 8, 10, 15;
2, 5, 4, 8, 9, 14;
2, 2, 4, 5, 7, 9, 13;
1, 2, 2, 4, 4, 8, 8, 13;
1, 1, 2, 2, 4, 4, 7, 9, 12;
0, 1, 1, 2, 2, 4, 4, 7, 8, 13;
1, 0, 1, 1, 2, 2, 4, 4, 7, 8, 12;
0, 1, 0, 1, 1, 2, 2, 4, 4, 7, 8, 12;
0, 0, 1, 0, 1, 1, 2, 2, 4, 4, 7, 8, 12;
0, 0, 0, 1, 0, 1, 1, 2, 2, 4, 4, 7, 8, 12;
....
For k = 1 and m = 1; T(1,1) = 42 because there are 42 parts of size 1 in the last section of the set of partitions of 11, since 10 + m = 11, so a(1) = 42. For k = 2 and m = 1; T(2,1) = 15 because there are 15 parts of size 2 in the last section of the set of partitions of 11, since 10 + m = 11, so a(2) = 15.
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Omar E. Pol, Feb 05 2012
STATUS
approved