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%I #20 Sep 08 2022 08:45:58
%S 1,3,4,7,11,18,29,47,76,23,99,22,21,43,64,7,71,78,49,27,76,3,79,82,61,
%T 43,4,47,51,98,49,47,96,43,39,82,21,3,24,27,51,78,29,7,36,43,79,22,1,
%U 23,24,47,71,18,89,7,96,3,99,2,1,3,4,7,11,18,29,47,76
%N Lucas numbers (mod 100).
%C The sequence has period 60.
%H G. C. Greubel, <a href="/A193686/b193686.txt">Table of n, a(n) for n = 1..10000</a>
%F a(n) = A000204(n) mod 100. - _Michel Marcus_, Sep 29 2013
%F a(n+60) = a(n). - _G. C. Greubel_, Feb 08 2016
%t Mod[LucasL[Range[100]], 100]
%o (PARI) a(n) = (fibonacci(n+1) + fibonacci(n-1)) % 100; \\ _Michel Marcus_, Sep 29 2013
%o (Magma) [Lucas(n) mod 100: n in [1..100]]; // _Vincenzo Librandi_, Feb 09 2016
%K nonn,easy
%O 1,2
%A _José María Grau Ribas_, Aug 02 2011
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