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Lucas numbers (mod 100).
1

%I #20 Sep 08 2022 08:45:58

%S 1,3,4,7,11,18,29,47,76,23,99,22,21,43,64,7,71,78,49,27,76,3,79,82,61,

%T 43,4,47,51,98,49,47,96,43,39,82,21,3,24,27,51,78,29,7,36,43,79,22,1,

%U 23,24,47,71,18,89,7,96,3,99,2,1,3,4,7,11,18,29,47,76

%N Lucas numbers (mod 100).

%C The sequence has period 60.

%H G. C. Greubel, <a href="/A193686/b193686.txt">Table of n, a(n) for n = 1..10000</a>

%F a(n) = A000204(n) mod 100. - _Michel Marcus_, Sep 29 2013

%F a(n+60) = a(n). - _G. C. Greubel_, Feb 08 2016

%t Mod[LucasL[Range[100]], 100]

%o (PARI) a(n) = (fibonacci(n+1) + fibonacci(n-1)) % 100; \\ _Michel Marcus_, Sep 29 2013

%o (Magma) [Lucas(n) mod 100: n in [1..100]]; // _Vincenzo Librandi_, Feb 09 2016

%K nonn,easy

%O 1,2

%A _José María Grau Ribas_, Aug 02 2011