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Number of vertices in truncated tetrahedron with faces that are centered polygons.
4

%I #59 Sep 08 2022 08:45:58

%S 1,21,95,259,549,1001,1651,2535,3689,5149,6951,9131,11725,14769,18299,

%T 22351,26961,32165,37999,44499,51701,59641,68355,77879,88249,99501,

%U 111671,124795,138909,154049,170251,187551,205985,225589,246399,268451,291781,316425

%N Number of vertices in truncated tetrahedron with faces that are centered polygons.

%C The sequence starts with a central vertex and expands outward with (n-1) centered polygonal pyramids producing a truncated tetrahedron. Each iteration requires the addition of (n-2) edges and (n-1) vertices to complete the centered polygon in each face. For centered triangles see A005448 and centered hexagons A003215.

%C This sequence is the 18th in the series (1/12)*t*(2*n^3-3*n^2+n)+2*n-1 for t = 2, 4, 6, ... gives A049480, A005894, A063488, A001845, A063489, A005898, A063490, A057813, A063491, A005902, A063492, A005917, A063493, A063494, A063495, A063496 and t = 36. While adjusting for offsets, the beginning sequence A049480 is generated by adding the square pyramidal numbers A000330 to the odd numbers A005408 and each subsequent sequence is found by adding another set of square pyramidals A000330. (T/2) * A000330(n) + A005408(n). At 30 * A000330 + A005408 = centered dodecahedral numbers, 36 * A000330 + A005408 = A193228 truncated octahedron and 90 * A000330 + A005408 = A193248 = truncated icosahedron and dodecahedron. All five of the "Centered Platonic Solids" numbers sequences are in this series of sequences. Also 4 out of five of the "truncated" platonic solid number sequences are in this series. - _Bruce J. Nicholson_, Jul 06 2018

%C It would be good to have a detailed description of how the sequence is constructed. Maybe in the Examples section? - _N. J. A. Sloane_, Sep 07 2018

%H Vincenzo Librandi, <a href="/A193218/b193218.txt">Table of n, a(n) for n = 1..10000</a>

%H OEIS, <a href="http://oeis.org/wiki/(Centered_polygons)_pyramidal_numbers"> (Centered_polygons) pyramidal numbers</a>

%H Wikipedia, <a href="http://en.wikipedia.org/wiki/Tetrahedral_number">Tetrahedral number</a>

%H Wikipedia, <a href="http://en.wikipedia.org/wiki/Triangular_number">Triangular number</a>

%H Wikipedia, <a href="http://en.wikipedia.org/wiki/Centered_polygonal_number">Centered polygonal number</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (4,-6,4,-1).

%F a(n) = 6*n^3 - 9*n^2 + 5*n - 1.

%F G.f.: x*(1+x)*(x^2+16*x+1) / (1-x)^4. - _R. J. Mathar_, Aug 26 2011

%F a(n) = 18 * A000330(n-1) + A005408(n-1) = A063496(n) + A006331(n-1). - _Bruce J. Nicholson_, Jul 06 2018

%t Table[6 n^3 - 9 n^2 + 5 n - 1, {n, 35}] (* _Alonso del Arte_, Jul 18 2011 *)

%t CoefficientList[Series[(1+x)*(x^2+16*x+1)/(1-x)^4, {x, 0, 50}], x] (* _Stefano Spezia_, Sep 04 2018 *)

%o (Magma) [6*n^3-9*n^2+5*n-1: n in [1..40]]; // _Vincenzo Librandi_, Aug 30 2011

%Y Cf. A260810 (partial sums).

%K nonn,easy

%O 1,2

%A _Craig Ferguson_, Jul 18 2011