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Numbers n such that A193101(n) = 5.
2

%I #10 Oct 12 2017 10:53:09

%S 37,115,122,166,334,372,541,1805,2532,2773,2861,3340,4148,4980,5157,

%T 5898,6522,6529,7557,10915,28415

%N Numbers n such that A193101(n) = 5.

%C It is quite possible that there are no more terms.

%H H. E. Salzer and N. Levine, <a href="https://doi.org/10.1090/S0025-5718-1968-0224578-6">Proof that every integer <= 452,479,659 is a sum of five numbers of the form Q_x = (x^3+5x)/6, x>= 0</a>, Math. Comp., (1968), 191-192.

%Y Cf. A004006, A193101.

%K nonn,more

%O 1,1

%A _N. J. A. Sloane_, Jul 15 2011