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A192421
Constant term of the reduction by x^2 -> x+1 of the polynomial p(n,x) defined below in Comments.
2
2, 0, 3, 1, 8, 8, 28, 43, 111, 204, 466, 924, 2007, 4109, 8740, 18136, 38240, 79799, 167643, 350664, 735554, 1540104, 3228459, 6762553, 14172272, 29691368, 62217172, 130356451, 273144327, 572305140, 1199164498, 2512579140, 5264623167, 11030890949
OFFSET
0,1
COMMENTS
The polynomial p(n,x) is defined by ((x+d)/2)^n + ((x-d)/2)^n, where d = sqrt(x^2+4). For an introduction to reductions of polynomials by substitutions such as x^2 -> x+1, see A192232.
FORMULA
From Colin Barker, May 12 2014: (Start)
a(n) = a(n-1) + 3*a(n-2) - a(n-3) - a(n-4).
G.f.: (2-2*x-3*x^2)/(1-x-3*x^2+x^3+x^4). (End)
a(n) = Sum_{j=0..n} T(n, j)*Fibonacci(j-1), where T(n, k) = [x^k] ((x + sqrt(x^2+4))^n + (x - sqrt(x^2+4))^n)/2^n. - G. C. Greubel, Jul 11 2023
EXAMPLE
The first five polynomials p(n,x) and their reductions are as follows:
p(0,x) = 2 -> 2.
p(1,x) = x -> x.
p(2,x) = 2 + x^2 -> 3 + x.
p(3,x) = 3*x + x^3 -> 1 + 5*x.
p(4,x) = 2 + 4*x^2 + x^4 -> 8 + 7*x.
From these, read a(n) = (2, 0, 3, 1, 8, ...) and A192422 = (0, 1, 1, 5, 7, ...).
MATHEMATICA
q[x_]:= x+1; d= Sqrt[x^2+4];
p[n_, x_]:= ((x+d)/2)^n + ((x-d)/2)^n (* A162514 *)
Table[Expand[p[n, x]], {n, 0, 6}]
reductionRules= {x^y_?EvenQ-> q[x]^(y/2), x^y_?OddQ-> x*q[x]^((y-1)/2)};
t = Table[FixedPoint[Expand[#1 /. reductionRules] &, p[n, x]], {n, 0, 30}]
Table[Coefficient[Part[t, n], x, 0], {n, 30}] (* A192421 *)
Table[Coefficient[Part[t, n], x, 1], {n, 30}] (* A192422 *)
LinearRecurrence[{1, 3, -1, -1}, {2, 0, 3, 1}, 40] (* G. C. Greubel, Jul 11 2023 *)
PROG
(Magma) R<x>:=PowerSeriesRing(Integers(), 40); Coefficients(R!( (2-2*x-3*x^2)/(1-x-3*x^2+x^3+x^4) )); // G. C. Greubel, Jul 11 2023
(SageMath)
@CachedFunction
def a(n): # a = A192421
if (n<4): return (2, 0, 3, 1)[n]
else: return a(n-1) +3*a(n-2) -a(n-3) -a(n-4)
[a(n) for n in range(41)] # G. C. Greubel, Jul 11 2023
CROSSREFS
KEYWORD
nonn
AUTHOR
Clark Kimberling, Jun 30 2011
STATUS
approved