

A192222


Fibonacci(2^n + 1).


4




OFFSET

0,2


COMMENTS

Product_{n>0} (1 + 1/a(n)) = 3/phi = A134973, where phi = (1+sqrt(5))/2 is the golden mean.


LINKS

Table of n, a(n) for n=0..8.
J. Sondow, Evaluation of Tachiya's algebraic infinite products involving Fibonacci and Lucas numbers, Diophantine Analysis and Related Fields 2011  AIP Conference Proceedings, vol. 1385, pp. 97100.
Y. Tachiya, Transcendence of certain infinite products, J. Number Theory 125 (2007), 182200.


FORMULA

a(n) = A000045(2^n + 1).


MATHEMATICA

Table[Fibonacci[2^n + 1], {n, 0, 10}] (* T. D. Noe, Jan 11 2012 *)


CROSSREFS

Cf. A000045 (Fibonacci numbers F(n)), A134973 (decimal expansion of 3/phi), A192223 (Lucas(2^n + 1)).
Sequence in context: A206830 A277436 A002665 * A241586 A000665 A058882
Adjacent sequences: A192219 A192220 A192221 * A192223 A192224 A192225


KEYWORD

nonn,easy,changed


AUTHOR

Jonathan Sondow, Jun 26 2011


STATUS

approved



