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A192035
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Numbers n with equal remainders of (product of divisors of n) mod (sum of divisors of n) and (product of proper divisors of n) mod (sum of proper divisors of n).
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1
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6, 14, 28, 51, 120, 260, 270, 496, 672, 679, 752, 924, 1260, 1320, 1540, 1960, 2055, 2262, 2651, 3808, 3948, 4381, 6413, 6435, 6944, 7900, 7980, 8010, 8128, 9809, 9945, 10242, 10920, 12690, 15456, 16830, 18018, 21728, 21970, 22320, 25296, 27930, 29190, 29792
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OFFSET
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1,1
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COMMENTS
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The even perfect numbers (A000396) are a subsequence.
The deficient numbers (A005100) in the sequence are 14, 51, 679, 752, 2055, 2651, 4381, 6413, 9809, 9945, 21970,... - Juri-Stepan Gerasimov, Jul 07 2011
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LINKS
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FORMULA
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EXAMPLE
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14 is in this sequence because ((1*2*7*14) mod (1+2+7+14))=(196 mod 24)=4 and ((1*2*7) mod (1+2+7))=(14 mod 10)=4.
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MATHEMATICA
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erQ[n_]:=Module[{divs=Divisors[n], ds=DivisorSigma[1, n]}, Mod[ Times@@ divs, ds] == Mod[ Times@@Most[divs], ds-n]]; Select[Range[2, 30000], erQ] (* Harvey P. Dale, Jun 13 2015 *)
Select[Range[2, 30000], Mod[(p = #^(DivisorSigma[0, #]/2)), (s = DivisorSigma[1, #])] == Mod[p/#, s - #] &] (* Amiram Eldar, Jul 21 2019 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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