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A191532
Triangle T(n,k) read by rows: T(n,n) = 2n+1, T(n,k)=k for k<n.
0
1, 0, 3, 0, 1, 5, 0, 1, 2, 7, 0, 1, 2, 3, 9, 0, 1, 2, 3, 4, 11, 0, 1, 2, 3, 4, 5, 13, 0, 1, 2, 3, 4, 5, 6, 15, 0, 1, 2, 3, 4, 5, 6, 7, 17, 0, 1, 2, 3, 4, 5, 6, 7, 8, 19, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 21, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 23, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 25, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 27
OFFSET
0,3
COMMENTS
We can build products of linear polynomials with these T(n,k) defining the absolute terms:
1+n = A000027(1+n) =2, 3, 4, 5, 6, 7,
n*(3+n)/2 = A000096(1+n) =2, 5, 9, 14, 20, 27,
n*(1+n)*(5+n)/6 = A005581(2+n) =2, 7, 16, 30, 50, 77,
n*(1+n)*(2+n)*(7+n)/24 = A005582(1+n) =2, 9, 25, 55, 105, 182,
n*(1+n)*(2+n)*(3+n)*(9+n)/120 = A005583(n) =2, 11, 36, 91, 196, 378,
n*(1+n)*(2+n)*(3+n)*(4+n)*(11+n)/720 = A005584(n)=2, 13, 49, 140, 336, 714,
FORMULA
T(n,k) = A002262(n-1,k).
sum_{k=0..n} T(n,k) = A000217(1+n).
EXAMPLE
1;
0,3;
0,1,5;
0,1,2,7;
0,1,2,3,9;
0,1,2,3,4,11;
CROSSREFS
Cf. A191302.
Sequence in context: A357892 A261158 A207543 * A333852 A179552 A119879
KEYWORD
nonn,easy,tabl
AUTHOR
Paul Curtz, Jun 05 2011
STATUS
approved