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 A191532 Triangle T(n,k) read by rows: T(n,n) = 2n+1, T(n,k)=k for k
 1, 0, 3, 0, 1, 5, 0, 1, 2, 7, 0, 1, 2, 3, 9, 0, 1, 2, 3, 4, 11, 0, 1, 2, 3, 4, 5, 13, 0, 1, 2, 3, 4, 5, 6, 15, 0, 1, 2, 3, 4, 5, 6, 7, 17, 0, 1, 2, 3, 4, 5, 6, 7, 8, 19, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 21, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 23, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 25, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 27 (list; table; graph; refs; listen; history; text; internal format)
 OFFSET 0,3 COMMENTS We can build products of linear polynomials with these T(n,k) defining the absolute terms: 1+n = A000027(1+n)                               =2,  3,  4,   5,   6,   7, n*(3+n)/2 = A000096(1+n)                         =2,  5,  9,  14,  20,  27, n*(1+n)*(5+n)/6 = A005581(2+n)                   =2,  7, 16,  30,  50,  77, n*(1+n)*(2+n)*(7+n)/24 = A005582(1+n)            =2,  9, 25,  55, 105, 182, n*(1+n)*(2+n)*(3+n)*(9+n)/120 = A005583(n)       =2, 11, 36,  91, 196, 378, n*(1+n)*(2+n)*(3+n)*(4+n)*(11+n)/720 = A005584(n)=2, 13, 49, 140, 336, 714, LINKS FORMULA T(n,k) = A002262(n-1,k). sum_{k=0..n} T(n,k) = A000217(1+n). EXAMPLE 1; 0,3; 0,1,5; 0,1,2,7; 0,1,2,3,9; 0,1,2,3,4,11; CROSSREFS Cf. A191302. Sequence in context: A208981 A261158 A207543 * A179552 A119879 A115714 Adjacent sequences:  A191529 A191530 A191531 * A191533 A191534 A191535 KEYWORD nonn,easy,tabl AUTHOR Paul Curtz, Jun 05 2011 STATUS approved

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